Molecular aggregates in which the individual molecules (monomers) are arranged in a regular fashion are of particular interest because of their unique electronic and spectroscopic properties, for example J-aggregates and H-aggregates. The J-aggregate is a one-dimensional molecular arrangement in which the transition moments of individual monomers are aligned parallel to the line joining their centers (end-to-end arrangement). The H-aggregate is also a one-dimensional array of molecules in which the transition moments of individual monomers are aligned parallel to each other but perpendicular to the line joining their centers (face-to-face arrangement). The most characteristic feature of J-aggregate is that they exhibit a narrow peak (J-band) red-shifted in the absorption spectrum with respect to the monomer absorption. The absorption spectrum of the H-aggregate consists of a blue-shifted band (generally is not as narrow as the J-band) with respect to the monomer absorption. The energy shift of the absorption bands of the aggregates has been explained by exciton theory.
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Vol = pi*r2*h = 2124 cubic units.
The formula for the volume of a rectangular solid, also known as a rectangular prism, is given by ( V = l \times w \times h ), where ( V ) represents the volume, ( l ) is the length, ( w ) is the width, and ( h ) is the height of the solid. To find the volume, simply multiply these three dimensions together.
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0.666 ^^^^ his answer mine 3 in 8 i believe. which is 0.375 you can get h,h,h h,t,h h,t,t h,h,t t,h,h t,t,h t,h,t t,t,t the ones you are looking for are h,h,t t,h,h h,t,h
f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2