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How do you differentiate x over 2?

Updated: 12/24/2022
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10y ago

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f(x) = x/2

Then the differential is lim h->0 [f(x+h) - f(x)]/h

= lim h->0 [(x+h)/2 - x/2]/h

= lim h->0 [h/2]/h

= lim h->0 [1/2] = 1/2

f(x) = x/2

Then the differential is lim h->0 [f(x+h) - f(x)]/h

= lim h->0 [(x+h)/2 - x/2]/h

= lim h->0 [h/2]/h

= lim h->0 [1/2] = 1/2

f(x) = x/2

Then the differential is lim h->0 [f(x+h) - f(x)]/h

= lim h->0 [(x+h)/2 - x/2]/h

= lim h->0 [h/2]/h

= lim h->0 [1/2] = 1/2

f(x) = x/2

Then the differential is lim h->0 [f(x+h) - f(x)]/h

= lim h->0 [(x+h)/2 - x/2]/h

= lim h->0 [h/2]/h

= lim h->0 [1/2] = 1/2

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10y ago
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User Avatar

Wiki User

10y ago

f(x) = x/2

Then the differential is lim h->0 [f(x+h) - f(x)]/h

= lim h->0 [(x+h)/2 - x/2]/h

= lim h->0 [h/2]/h

= lim h->0 [1/2] = 1/2

This answer is:
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