Are you talking about the angle A. If you are then at what point of the triangle is the angle A.
Let the triangle be ABC and suppose the median AD is also an altitude.AD is a median, therefore BD = CDAD is an altitude, therefore angle ADB = angle ADC = 90 degreesThen, in triangles ABD and ACD,AD is common,angle ADB = angle ADCand BD = CDTherefore the two triangles are congruent (SAS).And therefore AB = AC, that is, the triangle is isosceles.
Let the Isosceles Triangle be ∆ ABC with sides AB = AC = 14', and BC = 17' Draw a line bIsecting angle BAC. This line will be perpendicular to and bisect BC at point D. Then ∆ DBA (or ∆ DCA) is a right angled triangle with AB the hypotenuse. Angle ABD = Angle ABC is one of the two equal angles of the isosceles triangle. Cos ABD = BD/AB = 8.5/14 = 0.607143, therefore Angle ABC = 52.62° The third angle of the triangle is 180 - (2 x 52.62) = 180 - 105.24 = 74.76° The angles are therefore 52.62° , 52.62° and 74.76° .
The isosceles triangle theorem states: If two sides of a triangle are congruent, then the angles opposite to them are congruent Here is the proof: Draw triangle ABC with side AB congruent to side BC so the triangle is isosceles. Want to prove angle BAC is congruent to angle BCA Now draw an angle bisector of angle ABC that inersects side AC at a point P. ABP is congruent to CPB because ray BP is a bisector of angle ABC Now we know side BP is congruent to side BP. So we have side AB congruent to BC and side BP congruent to BP and the angles between them are ABP and CBP and those are congruent as well so we use SAS (side angle side) Now angle BAC and BCA are corresponding angles of congruent triangles to they are congruent and we are done! QED. Another proof: The area of a triangle is equal to 1/2*a*b*sin(C), where a and b are lengths of adjacent sides, and C is the angle between the two sides. Suppose we have a triangle ABC, where the lengths of the sides AB and AC are equal. Then the area of ABC = 1/2*AB*BC*sin(B) = 1/2*AC*CB*sin(C). Canceling, we have sin(B) = sin(C). Since the angles of a triangle sum to 180 degrees, B and C are both acute. Therefore, angle B is congruent to angle C. Altering the proof slightly gives us the converse to the above theorem, namely that if a triangle has two congruent angles, then the sides opposite to them are congruent as well.
Two sides and two interior angles will be congruent while the other side and interior angle will be different.
converse of the isosceles triangle theorem
Isosceles
true
It is isosceles.
It is isosceles.
Triangle ABC would be an isosceles. An isosceles triangle is defined as having two sides of equal length. This would also mean, then, that two angles in the triangle are also the same.
isosceles triangle
12squigally2
12 2
30 degrees
the sides of ABC are congruent to the sides of A'B'C'
converse of the isosceles triangle theorem