Are you talking about the angle A. If you are then at what point of the triangle is the angle A.
To prove that the base angles of an isosceles trapezoid are congruent, consider an isosceles trapezoid ( ABCD ) with ( AB \parallel CD ) and ( AD \cong BC ). By the properties of parallel lines, the angles ( \angle DAB ) and ( \angle ABC ) are consecutive interior angles formed by the transversal ( AD ) and ( BC ), respectively, thus ( \angle DAB + \angle ABC = 180^\circ ). Similarly, the angles ( \angle ADC ) and ( \angle BCD ) also sum to ( 180^\circ ). Since ( AD \cong BC ) and the trapezoid is isosceles, the two pairs of opposite angles must be equal, leading to ( \angle DAB \cong \angle ABC ) and ( \angle ADC \cong \angle BCD ), proving that the base angles ( \angle DAB ) and ( \angle ABC ) are congruent.
In an isosceles right triangle ( ABC ) with a right angle at ( B ) and ( AB ) having a slope of (-1), the slope of ( AC ) would be ( 1 ) since the two legs of the triangle are perpendicular. When the triangle is dilated with a scale factor of ( 1.8 ) from the origin, the slopes of the sides remain unchanged. Therefore, the slope of ( BC ), which is the leg opposite the right angle, remains ( 1 ).
Let the triangle be ABC and suppose the median AD is also an altitude.AD is a median, therefore BD = CDAD is an altitude, therefore angle ADB = angle ADC = 90 degreesThen, in triangles ABD and ACD,AD is common,angle ADB = angle ADCand BD = CDTherefore the two triangles are congruent (SAS).And therefore AB = AC, that is, the triangle is isosceles.
Let the Isosceles Triangle be ∆ ABC with sides AB = AC = 14', and BC = 17' Draw a line bIsecting angle BAC. This line will be perpendicular to and bisect BC at point D. Then ∆ DBA (or ∆ DCA) is a right angled triangle with AB the hypotenuse. Angle ABD = Angle ABC is one of the two equal angles of the isosceles triangle. Cos ABD = BD/AB = 8.5/14 = 0.607143, therefore Angle ABC = 52.62° The third angle of the triangle is 180 - (2 x 52.62) = 180 - 105.24 = 74.76° The angles are therefore 52.62° , 52.62° and 74.76° .
converse of the isosceles triangle theorem
Isosceles
true
It is isosceles.
It is isosceles.
Triangle ABC would be an isosceles. An isosceles triangle is defined as having two sides of equal length. This would also mean, then, that two angles in the triangle are also the same.
isosceles triangle
12 2
12squigally2
30 degrees
the sides of ABC are congruent to the sides of A'B'C'
converse of the isosceles triangle theorem