1.33 or 1(1/3)
multiply 2 six times , example 1 2 3 4 5 6 times=~ 2~2~2~2~2 ~ equals times so 2 times 2 times 2 times 2 times 2 times 2
2
Let's denote the number of marbles in the first line as (5). According to the rule given, each subsequent line has a number that is four less than twice the previous line. The sequence can be expressed as follows: Line 1: (5) Line 2: (2 \times 5 - 4 = 6) Line 3: (2 \times 6 - 4 = 8) Line 4: (2 \times 8 - 4 = 12) Line 5: (2 \times 12 - 4 = 20) Now, for the sixth line: (2 \times 20 - 4 = 36). Thus, there must be 36 marbles in the sixth line.
512
To find the least common denominator (LCD) of five-sixteenths (5/16) and one-sixth (1/6), we need to determine the least common multiple (LCM) of the denominators 16 and 6. The prime factorization of 16 is (2^4) and for 6, it is (2^1 \times 3^1). The LCM takes the highest power of each prime, which gives us (2^4 \times 3^1 = 48). Therefore, the LCD of five-sixteenths and one-sixth is 48.
The answer is 8. Basically how you get to the solution is simple. You have to divide 24 by 6 which is 4 if you know your multiplications of 4 and then you simply times it by 2 and then you get to the answer 8! :)
1/6 times 4 = 2/3 in its simplest form
4 to the seventh
It is one twenty fourth.
multiply 2 six times , example 1 2 3 4 5 6 times=~ 2~2~2~2~2 ~ equals times so 2 times 2 times 2 times 2 times 2 times 2
The answer is 5/6 times 6 and 4/5 = 5 and 2/3
do negative 4 times 4 6 times
If by four sixth you mean 4/6, the answer would be 8/6 or 1 and 2/6.
2
2/6 of 12 is 4.
Let's denote the number of marbles in the first line as (5). According to the rule given, each subsequent line has a number that is four less than twice the previous line. The sequence can be expressed as follows: Line 1: (5) Line 2: (2 \times 5 - 4 = 6) Line 3: (2 \times 6 - 4 = 8) Line 4: (2 \times 8 - 4 = 12) Line 5: (2 \times 12 - 4 = 20) Now, for the sixth line: (2 \times 20 - 4 = 36). Thus, there must be 36 marbles in the sixth line.
2 2/3 :)