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L = 5 and W = 5 since area is Length times width. L x W = 25 so 5 x 5 = 25
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How would you find the area and perimiter of a rectangle?
If the length and width are denoted by l and w, then area = lw ( the product of l time w) and perimeter = 2(l+w) that is, twice the sum of l and w.
What is the area of this rectangle 5x-3 W 14 L?
Area = L*W Area = 14* (5x-3) Area = 60x-42
Area of a rectangle?
A = Area l = length w = width A = (l)(w) Ex: L = 5 in. W = 2 in. A = ? A = l(w) A = 5(2) A = 10 in2
What area of this rectangle?
In order to find the area of a rectangle, you must follow the formula A= l x w where A is area, l is length, and w is width.
What is the length and width of a rectangular lot if its perimeter is 88m and its area is 480m2?
The equation for the perimeter is: 2(L + W) = 88m ie L + W = 44m So that L = 44 - W Then area = L*W = 480 m2 is equivalents to (44 - W)*W = 480 Or W2 - 44W + 480 = 0 which gives W = 20 or W = 24 if W = 20 then L = 24 and if W = 24 the L = 20 However, since conventionally, L>W, L = 24m, W = 20m
Area formula of a rectangle?
A = Area l = length w = width A = (l)(w) Ex: L = 5 in. W = 2 in. A = ? A = l(w) A = 5(2) A = 10 in2
How would you find the area and perimiter of a rectangle?
If the length and width are denoted by l and w, then area = lw ( the product of l time w) and perimeter = 2(l+w) that is, twice the sum of l and w.
What is the area of this rectangle 5x-3 W 14 L?
Area = L*W Area = 14* (5x-3) Area = 60x-42
Area of a rectangle?
A = Area l = length w = width A = (l)(w) Ex: L = 5 in. W = 2 in. A = ? A = l(w) A = 5(2) A = 10 in2
How do you find the length given area and width?
Length (L) equals area (A) divided by width (W); or L = A / W.
How do you simplify an expression for the perimeter and area of a rectangle?
Represent the length of the rectangle by L and the width by W. The perimeter = 2L + 2W = 2(L + W). The area = L x W.
What area of this rectangle?
In order to find the area of a rectangle, you must follow the formula A= l x w where A is area, l is length, and w is width.
What is the length and width of a rectangular lot if its perimeter is 88m and its area is 480m2?
The equation for the perimeter is: 2(L + W) = 88m ie L + W = 44m So that L = 44 - W Then area = L*W = 480 m2 is equivalents to (44 - W)*W = 480 Or W2 - 44W + 480 = 0 which gives W = 20 or W = 24 if W = 20 then L = 24 and if W = 24 the L = 20 However, since conventionally, L>W, L = 24m, W = 20m
If a carpet has an area of 48 square meters and the perimeter is 32 square meters what is the length and width?
Length (L) x Width (W) = Area 2*L+2*W = Perimeter 48/W=L (solved for L) 2*48/W+2*W=32 (inserted L into perimeter equation) 48+W^2=16*W (quadratic equation or factor) W=12 or 4 Therefore L=4 when W= 12 or L=12 when W=4 Length (L) x Width (W) = Area 2*L+2*W = Perimeter 48/W=L (solved for L) 2*48/W+2*W=32 (inserted L into perimeter equation) 48+W^2=16*W (quadratic equation or factor) W=12 or 4 Therefore L=4 when W= 12 or L=12 when W=4
How do you calculate surface area of a duct?
Dimension is : W * D* L IN MTR AREA SQ.MTR= (W+D) * 2 * L
What is the formula for finding the demensions of a rectangle given the area?
The area of a rectangle equals its length times its width (A = l*w), so if you have the area divided by the one of the sides equals the other side (l = A/w; w = A/l )
A rectangle is 4cm longer than it is wide what are the demesions if the area is 8cm?
Area of a rectangle = length x width If length = L and width = W, then Area = L x W For this case, the length is 4 cm longer than the width. Therefore, L = W + 4cm Replace length in the area equation at the top with this new L value: Area = (W + 4cm) x W Area = W^2 + (4cm) x W And area is 8 cm^2 (I assume you meant to say 8cm^2 is the area) Then: 8cm^2 = W^2 +4W This is a quadratic equation (because of the w^2 value), if you solve for W using the quadratic formula (Google it), you get W = 1.464cm Therefore, the length L = W + 4cm = 1.464cm + 4cm = 5.464cm Dimensions are L = 5.464cm and W = 1.464cm
