ab = 108 => a != 0, b != 0
so we CAN write b = 108 / a
a + 108 / a = 56
Multiply both side by a
a^2 + 108 = 56a. It's a simple quadratic equation, it will always have a solution over the Complex number, may be even REAL roots.
so when you are done with a, move on to b.
This is hardly abstract.
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The numbers are -10 and -70
-8 and -8
-3 and 6
15 and -3
-4 and -25
26
Two (or four) digits added together cannot equal 42. Two-digit numbers multiplied together cannot equal 82.
The numbers are -10 and -70
Urny ony
-8 and -8
-3 and 6
15 and -3
-4 and -25
95
-141
To solve this problem, we can set up a system of equations. Let's call the two numbers x and y. We know that xy = 32 and x + y = -12. By substituting the value of y from the second equation into the first equation, we get x(-12-x) = 32. Simplifying this equation, we get -12x - x^2 = 32. Rearranging the terms, we get x^2 + 12x - 32 = 0. By factoring or using the quadratic formula, we find the solutions x = -8 and x = 4. Therefore, the two numbers are -8 and -4.
-13