1 and 12
2 and 6
3 and 4
8 and 1.5
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17*2*114*12*72
15 and -3
2 and 53
1 2
There cannot be such a pair. a2 and b2 when multiplied together give a2b2 = (ab)2 So if two square numbers are multiplied together, their product is a square. 12 is not a square so the two numbers cannot exist.
-166
4*3*1 or 2*2*3
17*2*114*12*72
15 and -3
To solve this problem, we can set up a system of equations. Let's call the two numbers x and y. We know that xy = 32 and x + y = -12. By substituting the value of y from the second equation into the first equation, we get x(-12-x) = 32. Simplifying this equation, we get -12x - x^2 = 32. Rearranging the terms, we get x^2 + 12x - 32 = 0. By factoring or using the quadratic formula, we find the solutions x = -8 and x = 4. Therefore, the two numbers are -8 and -4.
1 x 12, 2 x 6, 3 x 4
2 and 53
1 2
There cannot be such a pair. a2 and b2 when multiplied together give a2b2 = (ab)2 So if two square numbers are multiplied together, their product is a square. 12 is not a square so the two numbers cannot exist.
The 4 numbers that give the same result when added or multiplied together are 1, 2, 3, and 6. When added together, they equal 12 (1 + 2 + 3 + 6 = 12), and when multiplied together, they also equal 12 (1 x 2 x 3 x 6 = 12). This is an example of a set of numbers that satisfy the condition of having the same sum and product.
4400 and 2
143 and 2