Without digging too deeply into this question, we can see immediately that it has no solution.
-- The largest possible sum of 3 digits is (9 + 9 + 9) = 27
-- 3 times (the largest possible sum of 3 digits) is (3 x 27) = 81
-- 3 times the largest possible sum of 3 digits is smaller than any 3-digit number.
21
2
The sum is 22 times the sum of the three digits.
27
27
Eighteen
27
21
2
The sum is 22 times the sum of the three digits.
18. The sum of its digits is 9. And yes, it is unique.
45
27
-8
27
-4
I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I