27
15 1 x 5 = 5, and 5 x 3 = 15
6 times
415
The answer to this question is at my website aim feliciano980
i am a two digit # my tens digit# is 3 times my ones digit #and the sum of my digit is 12 what am i
26.
804
27
To find the number of three-digit combinations, we consider the digits from 000 to 999. Each digit can range from 0 to 9, giving us 10 options for each of the three digits. Therefore, the total number of three-digit combinations is (10 \times 10 \times 10 = 1,000).
The sum is 22 times the sum of the three digits.
To form a three-digit number using the digits 0-9, the first digit cannot be 0 (as it would not be a three-digit number). Thus, the first digit can be any of the digits from 1 to 9 (9 options). The second and third digits can each be any digit from 0 to 9 (10 options each). Therefore, the total number of three-digit numbers is (9 \times 10 \times 10 = 900).
27
If one can repeat digits, each of the three positions in a three-digit password can be filled by any of the 10 digits (0-9). Therefore, the total number of three-digit numerical passwords is (10 \times 10 \times 10 = 1,000). Thus, there are 1,000 possible three-digit numerical passwords when digits can be repeated.
To form a three-digit number using the digits 1-7, we can choose any of the 7 digits for each of the three places (hundreds, tens, and units). Therefore, the total number of 3-digit combinations can be calculated as (7 \times 7 \times 7), which equals 343. Thus, there are 343 different three-digit numbers that can be formed using the digits 1-7.
it is 10
38977 is in ones place9 is in tens place (and is three times the number in thousands place)8 is in the hundreds place3 is in the thousands place7+9+8+3=27
To form a four-digit number using the digits 0, 1, 2, 3, 5, 6, and 7, we must ensure that the first digit is not 0 (to avoid creating a three-digit number). This leaves us with 6 options for the first digit (1, 2, 3, 5, 6, 7). For the remaining three digits, we can use any of the 7 digits (including 0) and can repeat digits. Thus, the total number of four-digit numbers is calculated as follows: (6 \times 7 \times 7 \times 7 = 6 \times 343 = 2058). Therefore, there are 2058 possible four-digit numbers.