It will take five. 2 x 2 x 2 x 2 x 2 = 32
They don't exist. 45 = 3*3*5 = 32*5.
360 = 23 x 32 x 5 = 2 x 2 x 2 x 3 x 3 x 5 so there are 6 prime numbers that are equal to 360 when multiplied not 3
That isn't possible. The sum of three odd numbers will always be odd. You can make the sum of 3 prime numbers equal to 32 if one of them is 2 (which is not odd).
To find two numbers that will give you 32 as their least common multiple (LCM), you need to consider the prime factorization of 32, which is 2^5. To get the LCM, you need to take the highest power of each prime factor that appears in the factorization of 32. Therefore, the two numbers that will give you 32 as their LCM are 2^5 and 1, as any number multiplied by 1 remains unchanged.
Five twos.
No, factors must be multiplied. The only prime factor of 32 is 2.
32 = 2 x 2 x 2 x 2 x 2
It will take five. 2 x 2 x 2 x 2 x 2 = 32
They don't exist. 45 = 3*3*5 = 32*5.
The prime factor of 32 is: 2
360 = 23 x 32 x 5 = 2 x 2 x 2 x 3 x 3 x 5 so there are 6 prime numbers that are equal to 360 when multiplied not 3
There are five prime numbers in the factorization of 32; all twos.
That isn't possible. The sum of three odd numbers will always be odd. You can make the sum of 3 prime numbers equal to 32 if one of them is 2 (which is not odd).
32 x 13 = 117
8x4=32 16x2=32 32x1=32
To find two numbers that will give you 32 as their least common multiple (LCM), you need to consider the prime factorization of 32, which is 2^5. To get the LCM, you need to take the highest power of each prime factor that appears in the factorization of 32. Therefore, the two numbers that will give you 32 as their LCM are 2^5 and 1, as any number multiplied by 1 remains unchanged.