Four different numbers that add up to 100 are 25, 30, 20, and 25. Another combination could be 10, 20, 30, and 40. Each set consists of distinct numbers that sum to the target value.
One way is: (4 + 4 + 6 + 9)^(100/50) = 23^2 = 529
81 and 9 if you add them. 4 and 25 if you multiply them.
1, 4, 9, 16, 25, 36, 42, 64, 81, 100
100 ÷ 4 = 25 → 24 numbers between 0 and 100 exclusive are divisible by 4 100 ÷ 6 = 16 2/3 → 16 numbers between 0 and 100 are divisible by 6 lcm(4, 6) = 12 → 100 ÷ 12 = 8 1/3 → 8 numbers between 0 and 100 are divisible by 4 and 6.
106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.
With 4 different numbers, 24.
As a product of its prime factors: 2*2*5*5 = 100
As a product of its prime factors: 2*2*5*5 = 100
One way is: (4 + 4 + 6 + 9)^(100/50) = 23^2 = 529
81 and 9 if you add them. 4 and 25 if you multiply them.
As a product of its prime factors: 2 * 2 * 5 * 5 = 100
Since 100/4 = 25, there are 25 numbers between 0 and 100 divisible by 4.
1+23-4+56+7+8+9+100
1, 4, 9, 16, 25, 36, 42, 64, 81, 100
100 ÷ 4 = 25 → 24 numbers between 0 and 100 exclusive are divisible by 4 100 ÷ 6 = 16 2/3 → 16 numbers between 0 and 100 are divisible by 6 lcm(4, 6) = 12 → 100 ÷ 12 = 8 1/3 → 8 numbers between 0 and 100 are divisible by 4 and 6.
4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76,80,84,88,92,96, 100
4. 4x25=100.