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How many different 3 letter permutations can be formed from the letters in the word count?
There are 5*4*3 = 60 permutations.
How many 3 number combinations are possible with 1234?
Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.
How many permutations are in the word stop?
There are 4*3*2*1 = 24 of them.
How many 4 digit numbers can you make with 3358?
12 numbers
How many permutations of letters in word swimming?
The number of permutations of the letters SWIMMING is 8 factorial or 40,320. The number of distinct permutations, however, due to the duplication of the letters I and M is a factor of 4 less than that, or 10,080.
How many four digit numbers can be formed from digits 1 2 3 4 if repeated is allowed and how many are odd numbers?
This is permutations with repetition. The answer is 4^4 = 256 total permutations. Since 2 of the digits used are odd (and 2 are even), then half of the possibilities will be odd: 128 odd numbers.
How many number combinations are there in the numbers from 1 to 4?
they are 24 you can make with the numbers 1-4 or any other 4 digits here they are123412431432142313421324213421432431241323412314312431423421341232413214423142134312432141324123* * * * *WRONG!These are permutations, not combinations. In a combination theorder of the digits does not matter so there is only one combination of 4 digits out of 4.
How may combinations can you make with 4 numbers?
If you are talking about the combination function C(x,y) then your answer would be 210. However, try to be a little more specific. If you intend for permutations of 4 digit numbers (order matters), then you would have 10000 permutations for the digits, given that none of the digits are equal to each other.
How many 4 number combinations can be made from four numbers?
If repetition is allowed and order is important, then you have essentially a base-4 number system, with the numbers ranging from 00004 to 33334. The quantity of permutations in this example is 44 = 256. If repetition is not allowed, but order is important, then it is 4! = 24. * * * * * The above answer is perfectly correct. But, as stated in the answer, for permutations. However, according to the mathematical definition of combinations (as opposed to permutations), the order is irrelevant to combinations. 1234 is the same as 1423 or 4213 etc. Consequently, there can be only one 4-number combination from 4 numbers
Given the numbers 12345 and 6 how many numbers of different permutations of lining up the letters?
6! = 6*5*4*3*2*1 = 720
How many possible permutations using the word bite?
4! Four factorial. 4 * 3 * 2 = 24 permutations ------------------------
How many permutations of five numbers can be made ftom six numbers?
The answer is 6P5 = 6!/(6-5)! = 6*5*4*3*2*1/1 = 720
How many number combinations can you make using the numbers 9, 3, 1, and 7?
To determine the number of combinations possible using the numbers 9, 3, 1, and 7, we can use the concept of permutations. A permutation is an arrangement of objects in a specific order. In this case, we want to find the number of permutations of all the numbers. The formula for permutations of n objects taken r at a time is given by: P(n, r) = n! / (n - r)! Where "!" denotes the factorial function. In this case, we have 4 numbers and we want to arrange all of them, so r = 4. P(4, 4) = 4! / (4 - 4)! = 4! / 0! = 4! / 1 = 4 * 3 * 2 * 1 = 24 Hence, there are 24 different number combinations that can be made using the numbers 9, 3, 1, and 7.
How many permutations of 0 6 4?
There are 6.
How many permutations are in the word math?
Since the word MATH does not have any duplicated letters, the number of permutations of those letters is simply the number of permutations of 4 things taken 4 at a time, or 4 factorial, or 24.
How many permutations are there in any 3 from 5?
There are 5P3 = 5!/2! = 5*4*3 = 60 permutations.
How many 4 digit permutations can you get with 10 numbers?
Since there are 10 numbers to fill 4 spots, each spot would have 10 choices for which number would fill it. We have (10)(10)(10)(10)=1000.
