3 and 53
56=2x2x2x7
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
The prime factorization of 56 is 2, 2, 2, and 7, so there there are two prime numbers, 2 and 7, that can evenly go into 56.
It will take four. 2 x 2 x 2 x 7 = 56
Numbers cannot "make" another number prime. If you are looking for the prime factorization of 56, it is 23 * 7.
The prime numbers (factors) of 56 are: 2 and 7
The prime numbers (factors) of 56 are: 2 and 7
3 and 53
LCM is 56, which is the multiple of the highest power of prime factors in the given numbers (23 x 7).
56=2x2x2x7
The least common multiple of the numbers 2,842 and 56 is 11,368.The least common multiple of the numbers 28, 42 and 56 is 168.
To find the least common multiple (LCM) of 2, 7, and 8, we first need to find the prime factorization of each number. The prime factorization of 2 is 2, 7 is already a prime number, and 8 is 2 x 2 x 2. Then, we take the highest power of each prime factor that appears in any of the numbers, which gives us 2^3 x 7 = 56. Therefore, the least common multiple of 2, 7, and 8 is 56.
56 does not have only three prime factors.
Oh honey, you must be new to the math game. The only way to add two prime numbers and get 56 is if you're playing make-believe. Prime numbers are loners, they don't like to share their factors with anyone else. So, sorry to burst your bubble, but there are no two prime numbers that can add up to 56. Better luck next time!
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
The prime factorization of 56 is 2, 2, 2, and 7, so there there are two prime numbers, 2 and 7, that can evenly go into 56.