{3,4,4,4,4,5} or {3,3,3,5,5,5} or {3,3.1,3.2,4.8,4.9,5}.
These are some examples of symmetric sets.
8 and 4
The mean is all of the numbers in the set of data added up then divided by how many numbers are in the set of data. It is also called the average. The range is the highest number in a set subtracted by the smallest. mean: Range: 2,4,10,and 5 2,4,10 and 4 2+4+10+4=20 10-4=6 20/4=5
To find the three numbers with a range of 6 and a mean of 4, we need to consider the spread of the numbers around the mean. Let's call the three numbers x, y, and z. Since the range is 6, the difference between the largest and smallest numbers is 6. To maximize the range while keeping the mean at 4, we can set x = 1, z = 7, and y = 4. Therefore, the three numbers are 1, 4, and 7.
25
{4,6,8}
8 and 4
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The numbers 3, 5, and 7 together have a range of 4 and a mean of 5.
The mean is all of the numbers in the set of data added up then divided by how many numbers are in the set of data. It is also called the average. The range is the highest number in a set subtracted by the smallest. mean: Range: 2,4,10,and 5 2,4,10 and 4 2+4+10+4=20 10-4=6 20/4=5
eight and twelveas mean is 10 then startwith 10 then divide the range of 4 by 2 = 2and take 2 off and add 2 on10 - 2 = 8 and 10 + 2 = 12Check:8 + 12 = 20 then divide those 2 numbers by that 2 so 20 / 2 = 10 mean12 - 8 = 4 range
The range is 4.
Range = 15 - 2 = 13
1, 5, 5, and 5 5+5+5+1=16/4=4 5-1=4
Add them all together, then divide by the number of the amount of numbers. Say you wanted the mean of 2, 3, and 4. You would add 2, 3, and 4 then divide by 3, because there are 3 numbers.
As there are two numbers, the range is the difference between themAs there are 2 numbers the mean is exactly in the middle of them.Thus half the range is less than the mean and half the range is greater than the mean.Thus the two numbers are 10 ± (4/2) = 10 ± 2 = 8 and 12.Algebraically, this can be seen:Let the two numbers be x and y with y > xThen:their range is y - x = 4; andtheir mean is (x + y) / 2 = 10{2} can be rearrange to give x + y = 10 × 2 → y + x = 20adding {3} to {1} yields: (y + y) + (-x + x) = 20 + 4 → 2y = 24 → y = 12subtracting {1} from {3} yields (y - y) + (x - -x) = 20 - 4 → 2x = 16 → x = 8→ the two numbers are 8 and 12.
25
{4,6,8}