If it is in the 83 series, try commands 3 and 4 on the CALC menu. Check your manual (or the online pdf manual) for more usage information.
30 frames per second is the minimum rate that it takes to fool the human eye into believing that a series of still pictures are moving.
Let the sum of series a1,.., an = A. Since ai >0. Then the maximum possible product of a1,..,an is = (A/n)n. This result basically comes the relation between the arithmetic mean and geometric mean of n positive numbers. A/n >= (a1...an)(1/n). The equality case of the above relation gives the maximum product (by raising the power by n on both sides).
The number 9 is the maximum number of beads on an abacus because it is the last number in the ones place before the tens place is reached.. The abacus is a tool that was used for arithmetic in ancient times. It is composed of a frame with a series of rods or wires on which beads are strung. The beads are used to represent numbers.
a sequential series of geometric shapes
5:9 ,i am not sure (;
The Balmer series is a series of spectral lines in the hydrogen spectrum that corresponds to transitions from energy levels n > 2 to the n=2 level. The longest wavelength in the Balmer series corresponds to the transition from n = ∞ to n = 2, known as the Balmer limit, which is approximately 656.3 nm.
The shortest wavelength radiation in the Balmer series is the transition from the n=3 energy level to the n=2 energy level, which corresponds to the Balmer alpha line at 656.3 nm in the visible spectrum of hydrogen.
The wavelength of the hydrogen atom in the 2nd line of the Balmer series is approximately 486 nm. This corresponds to the transition of an electron from the third energy level to the second energy level in the hydrogen atom.
The n4-n2 transition of hydrogen is in the cyan, with wavelength of 486.1 nm. blue = als
There are 4 Balmer lines with wavelengths in the visible region. They are red, aqua and two shades of violet. Other Balmer lines are in the ultraviolet. The red line corresponds to the transition from n = 3 to n = 2, the subsequent ones are from the 4, 5 and 6 levels to n = 2.
The longest wavelength in the Lyman series is the transition to n=2, which corresponds to the Lyman-alpha line at 121.6 nm. The shortest wavelength in the Balmer series is the transition to n=2, which corresponds to the Balmer-α line at 656.3 nm. Since the Lyman-alpha line has a longer wavelength than the Balmer-α line, they do not overlap.
The Balmer series for hydrogen consists of four spectral lines in the visible region. If there were a fifth line, its wavelength could be calculated using the formula 1/λ = RH(1/4^2 - 1/n^2), where RH is the Rydberg constant and n is the energy level. Plugging in the values, the fifth line wavelength would be smaller than the existing lines in the series.
I believe it to be the Balmer Series.
The Balmer series consists of visible spectral lines emitted by hydrogen atoms when electrons transition from higher to lower energy levels. The colors in the Balmer series include red (656.3 nm), blue-green (486.1 nm), and violet (434.0 nm) wavelengths.
The Balmer series corresponds to the spectral lines produced by hydrogen when electrons transition to the second energy level. The formula to calculate the wavelength for each line in the Balmer series is 1/λ = R(1/2^2 - 1/n^2), where n is the energy level and R is the Rydberg constant. For the fifth line (n=6), the wavelength would be approximately 434 nm.
The ratio of the first line of the Lyman series to the first line of the Balmer series in the hydrogen spectrum is 1:5.