the first or the last term of a proportion or series. a relative maximum or relative minimum value of a function in a given region.
Median is the middle number (e.g., in a series of numbers 1,2,3,4,5,6,7 - 4 is the median) Maximum is the highest number (7 in above example) Minimum is the lowest number (1 in above example) Range is the range of numbers (1-7, or possible the difference b/w max and min = 6 - see your textbook to verify)
Maximum daytime temperatures over a period of a year, or longer.
give the expansion of Taylor series
who discovered in arithmetic series
The Balmer series is a series of spectral lines in the hydrogen spectrum that corresponds to transitions from energy levels n > 2 to the n=2 level. The longest wavelength in the Balmer series corresponds to the transition from n = ∞ to n = 2, known as the Balmer limit, which is approximately 656.3 nm.
The shortest wavelength radiation in the Balmer series is the transition from the n=3 energy level to the n=2 energy level, which corresponds to the Balmer alpha line at 656.3 nm in the visible spectrum of hydrogen.
The wavelength of the hydrogen atom in the 2nd line of the Balmer series is approximately 486 nm. This corresponds to the transition of an electron from the third energy level to the second energy level in the hydrogen atom.
The n4-n2 transition of hydrogen is in the cyan, with wavelength of 486.1 nm. blue = als
There are 4 Balmer lines with wavelengths in the visible region. They are red, aqua and two shades of violet. Other Balmer lines are in the ultraviolet. The red line corresponds to the transition from n = 3 to n = 2, the subsequent ones are from the 4, 5 and 6 levels to n = 2.
The longest wavelength in the Lyman series is the transition to n=2, which corresponds to the Lyman-alpha line at 121.6 nm. The shortest wavelength in the Balmer series is the transition to n=2, which corresponds to the Balmer-α line at 656.3 nm. Since the Lyman-alpha line has a longer wavelength than the Balmer-α line, they do not overlap.
The Balmer series for hydrogen consists of four spectral lines in the visible region. If there were a fifth line, its wavelength could be calculated using the formula 1/λ = RH(1/4^2 - 1/n^2), where RH is the Rydberg constant and n is the energy level. Plugging in the values, the fifth line wavelength would be smaller than the existing lines in the series.
I believe it to be the Balmer Series.
The Balmer series consists of visible spectral lines emitted by hydrogen atoms when electrons transition from higher to lower energy levels. The colors in the Balmer series include red (656.3 nm), blue-green (486.1 nm), and violet (434.0 nm) wavelengths.
The Balmer series corresponds to the spectral lines produced by hydrogen when electrons transition to the second energy level. The formula to calculate the wavelength for each line in the Balmer series is 1/λ = R(1/2^2 - 1/n^2), where n is the energy level and R is the Rydberg constant. For the fifth line (n=6), the wavelength would be approximately 434 nm.
The ratio of the first line of the Lyman series to the first line of the Balmer series in the hydrogen spectrum is 1:5.
The ratio of the wavelengths of the last line in the Balmer series to the last line in the Lyman series is 1:5. The Balmer series is associated with transitions to the n=2 energy level, while the Lyman series is associated with transitions to the n=1 energy level in the hydrogen atom.