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1, 2, 113, 226.
2 + 113 = 115.
Only itself and one because 113 is a prime number
If there is a remainder of 8 when they divide into 113, then they must be factors of 113 - 8 = 105, but not factors of 113, and greater than 8: The factors of 105 are: 1, 3, 5, 7, 15, 21, 35, 105 The factors of 113 are: 1, 113 Thus the 3 numbers which divide 113 with a remainder of 8 are 15, 21, 35, 105 (oops, there are 4 numbers which satisfy the criteria - I never could count...)
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