The product of 2 and ( y ) is expressed mathematically as ( 2y ). This means you multiply the number 2 by the variable ( y ). The result will vary depending on the value of ( y ).
y is 2 less than the product of 3 and x
The product of two consecutive numbers, where the smaller number is ( y ), can be expressed as ( y(y + 1) ). This is because the next consecutive number after ( y ) is ( y + 1 ). Therefore, the product is ( y^2 + y ).
When multiplying powers, you add them! y4 times y6 = y10. Try it with y = 2: 2 to the fourth = 16, 2 to the sixth = 64 16 x 64 = 1024 = 2 to the tenth.
2y2
To find the product of (4x^4y^2) and (5y^4), multiply the coefficients and combine the like variables. The coefficients (4) and (5) multiply to give (20). For the variables, (y^2) and (y^4) combine to (y^{2+4} = y^6). Therefore, the product is (20x^4y^6).
y is 2 less than the product of 3 and x
The product of two consecutive numbers, where the smaller number is ( y ), can be expressed as ( y(y + 1) ). This is because the next consecutive number after ( y ) is ( y + 1 ). Therefore, the product is ( y^2 + y ).
It depends what the special product is. Common special products are: - perfect square trinomials ... x^2 + 2ax + a^2 = (x + a)^2 - difference of squares ... x^2 - y^2 = (x - y)(x + y)
When multiplying powers, you add them! y4 times y6 = y10. Try it with y = 2: 2 to the fourth = 16, 2 to the sixth = 64 16 x 64 = 1024 = 2 to the tenth.
(x+y)/2
In mathematics, XY square typically refers to the square of the product of two variables, X and Y. This can be represented as (XY)^2 or X^2 * Y^2. The result of squaring the product of X and Y is obtained by multiplying X and Y together and then squaring the result.
2y2
To find the product of (4x^4y^2) and (5y^4), multiply the coefficients and combine the like variables. The coefficients (4) and (5) multiply to give (20). For the variables, (y^2) and (y^4) combine to (y^{2+4} = y^6). Therefore, the product is (20x^4y^6).
It is 2y.
2(xy)
To write this algebraically: 7(y^3)|y = 2 Substitute 2 for y: 7(2^3) 2^3 = 8, so substitute 8 for (2^3): 7*8 = 56
It is: 7y+2