One half!
y=1/2 X-3.what is the slope?
If x is one of the numbers and y the other, then their sum is x+y = 53. So y = 53-x where x>0 and y>0 implying that x<53. Then, their product, P = x*y = x*(53-x) = 53*x - x2 for 0<x<53 [P is not defined for other values of x]
Take any fraction x/y and multiple that by it's reciprical, y/x. The result is x*y/x*y, or one. so any positive fraction multiplied by it's reciprical is one. hope that helped :)
common it's very easy !!Y = 1/2 X and X = -14and so :Y = 1/2 * -14Y = -7
0.5*xy
(x+y)/2
One half!
0.5xy or xy/2
1/2 (x+y)
The sum of x and y decreased by their product is (x + y)- xy.
y=1/2 X-3.what is the slope?
x= y (1/2) or x= y/2 or x= y times 1/2 or x= 1/2y
y = 1/2
A reciprocal. x is the reciprocal of y means that x*y = 1 Also, if x is the reciprocal of y then y is the reciprocal of x.
If x is one of the numbers and y the other, then their sum is x+y = 53. So y = 53-x where x>0 and y>0 implying that x<53. Then, their product, P = x*y = x*(53-x) = 53*x - x2 for 0<x<53 [P is not defined for other values of x]
Take any fraction x/y and multiple that by it's reciprical, y/x. The result is x*y/x*y, or one. so any positive fraction multiplied by it's reciprical is one. hope that helped :)