Q: What Volume of water is needed for a tank 8 feet long by 2 feet wide by 1 foot deep?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

The volume of the pool is 2,290.2 cu ft and has a maximum capacity of 17,133.2 gallons of water.

21.206 cubic feet.

Volume = 1240.5 = 24 cubic feet is needed

volume of soil needed = 38*5*1=190sq ft .12" = 1 feet

If the pool is 8 feet in the deep end and 3 feet in the shallow end, the total volume will be about 38,507 gallons of water.

Related questions

The volume of the pool is 2,290.2 cu ft and has a maximum capacity of 17,133.2 gallons of water.

21.206 cubic feet.

Volume = 1240.5 = 24 cubic feet is needed

volume of soil needed = 38*5*1=190sq ft .12" = 1 feet

The volume of an area 24 feet round and 45 inches deep is: 1,700 cubic feet.

If the pool is 8 feet in the deep end and 3 feet in the shallow end, the total volume will be about 38,507 gallons of water.

A round pool with these dimensions and 4.5 feet deep has a volume of 265,500 gallons of water.

If the depth is 4 feet throughout the whole pool, the total volume will be about 8,976 gallons of water.

To calculate the volume of soil needed to fill the well, you can use the formula for the volume of a cylinder: V = πr^2h, where r is the radius (half the diameter) and h is the height. In this case, the radius is 2 feet and the height is 32 feet. Therefore, the volume of soil needed would be approximately 804.25 cubic feet.

You need more information. But, let's assume the pool is 8 feet deep at the deep end and 3 feet at the shallow end. If the pool is rectangular, the total volume will be 28,798 gallons of water.

Three feet of water in a 12-foot round pool is about 2,550 gallons.

The volume of a pool measuring 44 feet long x 9 feet wide x 8 feet deep is 3,168 cubic feet. This pool could hold a maximum of about 23,700 US gallons of water.