2m+1
All integers are not odd.
If x is the smallest odd integer, then x = 2n + 1 for some integer n. Then the next two odd integers are 2n + 3 and 2n + 5 So the question then becomes: 2n+1 + (2n+3) + (2n+5) = 45 or 6n + 9 = 45 to be solved for n and thence the smallest of the three consecutive odd integers.
Are not all integers spaced out to be odd then even then odd then even etc (eg 1,2,3,4,5,6,7,8,9,10, etc) and therefore there is no such thing as two consecutive odd integers.
The two odd integers are 57 and 59.
2m+1
All integers are not odd.
2x + 1
If x is the smallest odd integer, then x = 2n + 1 for some integer n. Then the next two odd integers are 2n + 3 and 2n + 5 So the question then becomes: 2n+1 + (2n+3) + (2n+5) = 45 or 6n + 9 = 45 to be solved for n and thence the smallest of the three consecutive odd integers.
Are not all integers spaced out to be odd then even then odd then even etc (eg 1,2,3,4,5,6,7,8,9,10, etc) and therefore there is no such thing as two consecutive odd integers.
The sum of any three consecutive odd integers is going to give an odd result. It is impossible for the sum of an odd number of odd integers to equal an even number.
No. For example, 5 is an odd integer and 3 is an odd integer, yet 5/3 is neither an integer nor odd (as odd numbers are, by definition, integers).
find the two consecutive odd integers with a sum of 152
The two odd integers are 57 and 59.
The concept of "even" and "odd" applies to integers, not to fractions in general.The concept of "even" and "odd" applies to integers, not to fractions in general.The concept of "even" and "odd" applies to integers, not to fractions in general.The concept of "even" and "odd" applies to integers, not to fractions in general.
17 (odd integer) + 19 (odd integer) = 36 17 and 19 are consecutive odd integers.
2/3x3 is one possibility.And incidentally, there is no such thing as an interger: the word in integer!