You can use Snell's Law. Note that you need two angles for this - the incoming angle, and the outgoing angle.
The classical problem of angle trisection cannot be solved. If it were possible, it would provide the solution to a cubic equation. (-but it isn't and it won't!)
It depends on what angle. The main angles of a rectangle are all 90 degrees and knowing that does not help. If however, the angle in question is the angle made by the diagonal with one of the sides, then it is possible to use a basic trigonometric ratio to work out the length. Details will depend on which angle is given.
you subtract the other angle from 180 and that should give you your answers
Use the equation 180(n-2)/n, where n is the number of sides in the figure.
To find the angle in the work done, you can use the formula: work = force * distance * cos(angle). Rearrange the formula to solve for the angle: angle = cos^(-1)(work / (force * distance)). Substituting the values of work, force, and distance into the equation will give you the angle.
you use SOHCAHTOA to work out whether you need to use sine or cosine (as you already have the hypotenuse) you then use the diagonal as the hypotenuse and use the equation of either: sin(angle)=missing side/diagonal cos(angle)=missing side/diagonal you then take the answer and mark it on the two sides that it applies to. you use the value you just found along with the diagonal in the Pythagoras theorem equation (in this case it will be b2 = diagonal2-other side2). you then have the value of every side so you just add them all together.
It really depends on the angle. If the angle is at the point where the two equal sides intersect then you can divide the triangle into two equal parts (forming a right angle with the base), divide the angle by two, then use the following equation(side*arccos(your angle/2))*((side*arcsin(your angle/2)))if the angle is not where the two equal sides intersect then you can divide the triangle into two equal parts (from the point where the two equal sides intersect down to a right angle with the base) then use the following equation.(side*arcsin(your angle)*(side*arccos(your angle))
You can use Snell's Law. Note that you need two angles for this - the incoming angle, and the outgoing angle.
The phase angle in a wave equation can be found by comparing the equation to a standard form, such as (y = A \sin(\omega t + \phi)), where (\phi) is the phase angle. This angle represents the horizontal shift of the wave relative to a standard sine curve. You can determine the phase angle by comparing the equation to the standard form and identifying the value that corresponds to the horizontal shift in the wave.
Work is calculated using the equation: Work = Force x Distance x Cos(θ), where Force is the magnitude of the force applied, Distance is the distance over which the force is applied, and θ is the angle between the force and the direction of motion.
The equation for work is work = force × displacement × cosθ, where θ is the angle between the force and displacement vectors. If you want to calculate work done over a specific time period, you would need to know the force exerted over that time period and the corresponding displacement.
When finding a supplementary angle, you can simply use a + b = c. C will always equal 180. In this case A is 91.4. So your equation is:91.4 + B = 180180 - 91.4 = BB = 88.6.The supplementary angle is 88.6.
The classical problem of angle trisection cannot be solved. If it were possible, it would provide the solution to a cubic equation. (-but it isn't and it won't!)
It depends on what angle. The main angles of a rectangle are all 90 degrees and knowing that does not help. If however, the angle in question is the angle made by the diagonal with one of the sides, then it is possible to use a basic trigonometric ratio to work out the length. Details will depend on which angle is given.
you subtract the other angle from 180 and that should give you your answers
(360) / (180 - n) n= interior angle in this case it will work like this: 360/(180-120) 360/(60) 6, so the number of sides is six.