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42 and 49 are both divisible by 7. 42/49= 6/7
No. Both are divisible by 7.
Both 49 and 100 are divisible by 1 and themselves. In addition, 49 is divisible by 7 (7 x 7 = 49), and 100 is divisible by 2 and 5 (2 x 50 = 100, 5 x 20 = 100). So, the numbers that will divide into both 49 and 100 are 1 and the numbers 7, 2, and 5.
All multiples of 49 are divisible by it. Ex: 49, 98, 147 etc
True. A number that is divisible by both 3 and 4 is also divisible by their least common multiple, which is 12. Since 12 can be expressed as (3 \times 4), any number meeting the criteria of being divisible by both 3 and 4 will indeed be divisible by 12.
42 and 49 are both divisible by 7. 42/49= 6/7
No. Both are divisible by 7.
Both 49 and 100 are divisible by 1 and themselves. In addition, 49 is divisible by 7 (7 x 7 = 49), and 100 is divisible by 2 and 5 (2 x 50 = 100, 5 x 20 = 100). So, the numbers that will divide into both 49 and 100 are 1 and the numbers 7, 2, and 5.
both are divisible by seven. 42/49 = 6/7
No. 49 is only divisible by 1, 7 and 49.
Yes, because 12 is divisible by 2 and 6.
Besides 49 & 98? The numbers divisible by 49 are infinite.
No, they are both divisible by 7. 49/7=7 770/7=110
12. 12 is evenly divisible by both 12 and 4.
Not always because 30 is divisible by 2 and 6 but not by 12
All multiples of 49 are divisible by it. Ex: 49, 98, 147 etc
1,2,3,4,6,12