1, 2, 5, 10, 13, 26, 65, 130
The number 5 goes into both 65 and 130 (65/5 = 13, 130/5 = 26)
26 is not divisible by 9 because the sum of the digits is not divisible by
No. To be divisible by 10, the last digit must be a zero (0); 65 ends with a five (5) and thus is not divisible by 10.
Yes, by these numbers: 1, 2, 5, 10, 13, 25, 26, 50, 65, 130, 325, 650.
1 and 13.
Two numbers are considered relatively prime if they share no common factors other than 1. In this case, 26 and 39 are not relatively prime because they have a common factor of 13 (13 is a factor of both 26 and 39). Therefore, 26 and 39 are not relatively prime.
no, it is divisible by 1, 5, 13, 65
1, 2, 5, 10, 13, 26, 65, 130
The number 5 goes into both 65 and 130 (65/5 = 13, 130/5 = 26)
26 is not divisible by 9 because the sum of the digits is not divisible by
No.Is not divisible bye 26. :)
39, 78, 117, 195, 312 and 936 are divisible by three.
26 is divisible by any of its factors which are: 1, 2, 13 and 26.
A number divisible by both 2 and 5 will be divisible by their product (2 x 5), which is 10. Any number divisible by 10 ends in 0. The only number listed that ends in 0 is 110.
No. To be divisible by 10, the last digit must be a zero (0); 65 ends with a five (5) and thus is not divisible by 10.
Yes, by these numbers: 1, 2, 5, 10, 13, 25, 26, 50, 65, 130, 325, 650.