1 and 13.
They are both divisible by 13.
no, it is divisible by 1, 5, 13, 65
65 is divisible by 1, 5, 13, 65.
65% as a fraction = 65/100 simplify the numerator and denominator by a number they are both divisible by. so, 65/ 5=13 and 100/5= 20 so 65% as a reduced fraction is 13/20
It is the fact that 13*5 = 65.
All multiples of 65, which is an infinite number.
1, 5, 13, 25, 65, 325
Yes. All numbers ending in 5 or 0 are divisible by 5.65/5 = 13
455 is divisible by its factors which are: 1, 5, 7, 13, 35, 65, 91, 455
First, look for a factor. The most obvious would be 5, because the number ends in a five, so must be divisible by 5. 65/5 = 13, so the other factor will be 13. So 65 / \ 5 13 and since both 5 and 13 are prime numbers, the tree can't go on any further.
1, 5, 13, 17, 65, 85, 221, 1105
1, 5, 13, 17, 65, 85, 221, 1105