Q: What are 2 equations using pi?

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Rem4 x 3.14 ember the Circle Equations C = 2 pi r A = pi r^(2) If 'r' (radius) = 2 units then C = 2 pi x 2 = 4 x pi = 4 x 3.14 = 12.56 units. A = pi 2^(2) = 3.14 x 4 = 12.56 units^(2) NB pi = 3.141592.... It is an irrational constant. However, when learning circle equations you are usually given pi = 3.14 , or 3.1416 or 22/7, These are only approximations given for ease of learning.

Area = pi R2Circumference = 2 pi RArea/Circumference = pi R2/2pi R = 1/2 R

Trigonometric equations often have infinitely many solutions, due to the periodicity of the functions. Take a simple example, sin x = 0. This equation is satisfied by an angle of zero, but also by an angle of pi, 2 x pi, 3 x pi, etc. (this is in radians; the equivalent in degrees would be 0Â°, 180Â°, 360Â°, etc.). Once you find two base solutions (in this case 0 and pi), repeatedly adding the length of the period (in this case, 2 pi, equivalent to 360Â°) will give you additional solutions.

Circumference of a circle = 2*pi*radius or diameter*pi

a=pi r²a=pi (d/2)²

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Rem4 x 3.14 ember the Circle Equations C = 2 pi r A = pi r^(2) If 'r' (radius) = 2 units then C = 2 pi x 2 = 4 x pi = 4 x 3.14 = 12.56 units. A = pi 2^(2) = 3.14 x 4 = 12.56 units^(2) NB pi = 3.141592.... It is an irrational constant. However, when learning circle equations you are usually given pi = 3.14 , or 3.1416 or 22/7, These are only approximations given for ease of learning.

Here are the three circle equations, in words and equations. Circumfwerence - pi X diameter C = pi d Circumference = two X pi X radius C = 2pi r Area = pi X radius squared A = pi r^(2) NB It is only the radial value that is squared ; NOT 'pi'. NB pi is a constant at 3.141592..., usually approximated to 3.14 or 3.1416.

Pi is 3.14159265415.... and so on and so forth. Pi is more commonly used as 3.14 in equations.

Einstein may have used pi (Ï€)in his equations but he had no involvement in the creation or application of pi.

Remember the circle equations. A = pi r^2 C = 2 pi r = pi d ( Hence d = 2r) Algebraically rarranging r = sqrt(A/pi) 2r = d = 2(sqrt(A/pi)) Hence d = 2(sqrt(28.26 / 3.141592...)) d = 2(sqrt(8.99543....) d = 2(2.999239...) d = 5.99847.... ~ 6 The answer!!!!!

Area = pi R2Circumference = 2 pi RArea/Circumference = pi R2/2pi R = 1/2 R

Trigonometric equations often have infinitely many solutions, due to the periodicity of the functions. Take a simple example, sin x = 0. This equation is satisfied by an angle of zero, but also by an angle of pi, 2 x pi, 3 x pi, etc. (this is in radians; the equivalent in degrees would be 0Â°, 180Â°, 360Â°, etc.). Once you find two base solutions (in this case 0 and pi), repeatedly adding the length of the period (in this case, 2 pi, equivalent to 360Â°) will give you additional solutions.

Remember and comit to memory the two circle equations. C = pi d = 2 pi r & A = pi r^(2) Taking the first equation C = pi d d = 2.5 pi = 3.141592..... ~ 3.14 Hence C = 3.14 * 2.5 C = 7.85 units.

circumference of a circle = pi*diameter or 2*pi*radius

Circumference of a circle = 2*pi*radius or diameter*pi

a=pi r²a=pi (d/2)²

If you're looking for the volume of the cylinder, use the formula:Area*height = (pi*radius2)*heightto find the radius you just divide the diameter by 2.Using your values:Volume=[pi*(18/2)2] * 18 = 1458*pi = 4580.44If you're looking for the surface area, use the formula:Surface Area = circumference*height + 2(Flat area) = pi*diameter*height + 2(pi*radius2)Using your values:Surface Area = pi*18*18+2[pi*(18/2)2] = 324*pi + 2*1458*pi = 3240*pi = 10179