There is only one even Prime number: 2. So, representing 20 as a sum of even prime numbers would be 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2.
148
It is 75.
17 and 3 are two prime numbers whose sum is 20. Their product is 51.
17
(2,3) and (2,5) are the two pairs such that the sum of their elements is a prime number.
There is only one prime number and it is '2' You cannot have any other even prime number
148
It is 75.
17 and 3 are two prime numbers whose sum is 20. Their product is 51.
3 + 17 = 20
They are: 2+7+11 = 20
To find the sum of all prime numbers between 20 and 40, we first list out the prime numbers in that range: 23, 29, 31, 37. Then, we simply add them together: 23 + 29 + 31 + 37 = 120. Therefore, the sum of all prime numbers between 20 and 40 is 120.
The only even prime number is 2. It happens twice in the prime factorization of 20.
Seven of them.
600 * * * * * It is, in fact, 639
3 and 17
To write a program in QBasic that prints the sum of the even numbers from 1 to 20 in reverse order, you can follow these steps: DIM sum AS INTEGER sum = 0 FOR i = 20 TO 2 STEP -2 sum = sum + i NEXT i PRINT "The sum of even numbers from 1 to 20 is: "; sum This program initializes the sum to zero, iterates from 20 down to 2 in steps of -2 (to capture even numbers), adds each even number to the sum, and finally prints the result.