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What is the probability of pulling a black ball and then a green ball if there are 3 red balls 3 green balls 3 blue balls and 3 black balls?
3/12*3/11 = 9/132, or 6.818%.
How can you make 3 squares with 9 matchsticks?
Arrange them in the form of a triangular prism. Since this is a 3-dimensional object you will probably need some plasticine or bluetack balls to hold things together.
Canister holds 3 tennis balls the diameter of the balls is the same as the diameter of the cylinder 6 cm how much space in the cylinder is not taken?
Canister holds 3 tennis balls the diameter of the balls is the same as the diameter of the cylinder 6 cm how much space in the cylinder is not taken? Since 3 tennis balls fit in the cylinder, the height of the cylinder is 3 * the diameter of a tennis ball Volume of Sphere = 4/3 * Π radius^3 Volume of Cylinder = height * Π radius^2 The diameter of a tennis ball is 6 cm The radius is 3 cm. Volume of 3 balls = 3* 4/3 * Π * radius^3 Volume of 3 balls = 3* 4/3 * Π * 3^3 Height of Cylinder = 3 * 6 cm = 18 cm Volume of cylinder = 18 * Π * 3^2 Space in the cylinder is not taken = Volume of cylinder - Volume of 3 balls Do the math, you should get 169.6 cc for the space in the cylinder is not taken.
3 red and 4 blue balls are in a basket A member of PPTeam is drawing balls from the basket What is the probablity of getting the 3 red balls simultaneously?
The probability is 3/7 * 2/6 * 1/5 = 1/35.
A bag contains 3 red balls and 4 green balls randomly draw one ball then replace it and randomly draw a second what is the percentage?
Drawing one red ball out of a bag that contains 3 red balls and 4 green balls is 3 in 7. If we are to randomly select one ball out of the bag and replace it (I assume with the same ball) then there are still 3 red balls and 4 green balls. The odds are still 3 in 7. It doesn't matter how many times you draw. Every time you draw a ball you have a 3 in 7 chance of pulling out a red ball.
