The probability is zero, because there are no red balls in the bag.
If you draw enough balls, without replacement, the probability is 1.The answer depends onhow many balls are drawn, andwhether or not they are replaced.Unfortunately, your question gives no information on these matters.
The probability is B*G/(B+G+R)^2where B = number of Blue marbles G = number of Green marbles and R = number of marbles of other colours.
The probability of a simple event is the number of ways to succeed over the total possibilities. So, there are three white balls, and ten balls total. So: P(white) = 3/10
1/4 chance
The probability is zero, because there are no red balls in the bag.
If you draw enough balls, without replacement, the probability is 1.The answer depends onhow many balls are drawn, andwhether or not they are replaced.Unfortunately, your question gives no information on these matters.
2
This is a law of addition probability which states that the probability of A or B equals the probability of A plus the probability of B minus the probability of A and B. Written in mathematical terms, the equation is: P(AorB) = P(A) + P(B) - P(AnB) where P(AnB) = 0 (since you can not pull out a green and black ball at the same time). Let P(A) = Probability of drawing the green ball & let P(B) = Probability of drawing the black ball. Total outcomes is 17. So, P(A) = 4/17 & P(B) = 6/17. Therefore P(green or black) = 4/17 + 6/17 = 10/17.
It is 1/7 if a ball is selected at random.
1
The probability is B*G/(B+G+R)^2where B = number of Blue marbles G = number of Green marbles and R = number of marbles of other colours.
The probability of a simple event is the number of ways to succeed over the total possibilities. So, there are three white balls, and ten balls total. So: P(white) = 3/10
1/4 chance
3 out of 13 or 3/13
2/7 = 28.57%
zero