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You will only get an integer solution to this question is the number is divisible by 3. In that case the three numbers will by x/3-1, x/3 and x/3+1. Here, 63/3 = 21 so the three numbers are 20, 21 and 22.

Q: What are 3 consecutive whole numbers whose sum is 63?

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You probably want to know "What are the 3 consecutive whole numbers whose sum is 72 ?" They are 23, 24, and 25.

The numbers are 9, 11 and 13.

The numbers are 3, 4 and 5.

They are: 146+147+148 = 441

124 + 125 + 126 = 375

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There is no set of 8 consecutive whole numbers whose sum is 75.

You probably want to know "What are the 3 consecutive whole numbers whose sum is 72 ?" They are 23, 24, and 25.

That isn't possible.

The numbers are 9, 11 and 13.

The numbers are 3, 4 and 5.

The numbers are 746, 747 and 748, as well as 745, 747 and 749 using only consecutive odd whole numbers.

They are: 146+147+148 = 441

124 + 125 + 126 = 375

For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.

9+10+11= 30

There are no two consecutive whole numbers that sum to 142.With two consecutive whole numbers, one is even and the other odd, and their sum will be odd, but 142 is even.Two consecutive even numbers that sum to 142 are 70 and 72.

There are two consecutive even numbers. The numbers are 62 and 64.