6, 7, 8
Detailed Answer:
Assume the numbers are: n-1, n, n+1 ...... (1)
then, (n-1)2 + n2 + (n+1)2 = 149
3n2 + 2 = 149
3n2 = 147
n2 = 49
n = 7 (or -7 but not valid)
substitute in eq 1
the answer is as above 6, 7, 8
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The numbers are 12 and 14.
The numbers are 8 and 9.
6,7,8 those numbers squared are 36,49,64 which add to 149
Consecutive numbers are whole numbers whose difference is 1.
Any pair of consecutive numbers will have an odd total. 10 and 12 are consecutive even numbers that total 22.