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What are two consecutive numbers whose squares differ by 31?
15 and 16
What are the two consecutive whole numbers whose squares differ by 49?
24 and 25, which are (49-1)/2 and (49+1)/2
What are 2 consecutive numbers whose squares differ by 17?
The difference between the squares of two consecutive integers j and j+1 is |2j+1|. There are therefore two such pairs where this quantity is 17:-9 and -88 and 9
What are two consecutive numbers whose sum is 126?
There are two consecutive even numbers. The numbers are 62 and 64.
What is two consecutive numbers whose sum is 489?
The numbers are 244 and 245.
What are two consecutive numbers whose squares differ by 31?
15 and 16
What are two consecutive numbers whose squares differ by 125?
62 and 63
What are the two consecutive numbers whose squares add to 365?
The numbers are 13 and 14.
What are the two consecutive whole numbers whose squares differ by 49?
24 and 25, which are (49-1)/2 and (49+1)/2
What are two consecutive numbers whose squares diffee by 35?
17 and 18
What are 2 consecutive numbers whose squares differ by 17?
The difference between the squares of two consecutive integers j and j+1 is |2j+1|. There are therefore two such pairs where this quantity is 17:-9 and -88 and 9
What are two consecutive positive even numbers the sum of whose squares is 340?
The numbers are 12 and 14.
What are the 2 consecutive positive even numbers the sum of whose squares is 340?
The numbers are 12 and 14.
What two consecutive numbers whose squares differ by 25?
Let the two consecutive numbers be ( n ) and ( n + 1 ). The difference of their squares can be expressed as ( (n + 1)^2 - n^2 ), which simplifies to ( 2n + 1 ). Setting this equal to 25, we get the equation ( 2n + 1 = 25 ). Solving for ( n ), we find ( n = 12 ), so the two consecutive numbers are 12 and 13.
What are two consecutive numbers whose squares differ by 17?
Let's call n the first one the problem is (n+1)2-n2=17 = 2n+1 then n = 8
What is two consecutive numbers whose squares differ by 25?
Let's denote the two consecutive numbers as x and x+1. The square of the first number is x^2, and the square of the second number is (x+1)^2. According to the given condition, their squares differ by 25, so we have the equation (x+1)^2 - x^2 = 25. Simplifying this equation, we get x^2 + 2x + 1 - x^2 = 25, which simplifies to 2x + 1 = 25. Solving for x, we find x = 12. Therefore, the two consecutive numbers are 12 and 13.
What is the consecutive numbers in mathematical algebra?
Consecutive numbers are whole numbers whose difference is 1.
