24, XXIV (Roman numerals) and 11000 (binary code).
To find the number of ways to choose 3 posters from 24, you can use the combination formula, which is given by ( C(n, r) = \frac{n!}{r!(n - r)!} ). Here, ( n = 24 ) and ( r = 3 ). Plugging in the values, we get ( C(24, 3) = \frac{24!}{3!(24 - 3)!} = \frac{24 \times 23 \times 22}{3 \times 2 \times 1} = 2024 ). Thus, there are 2024 ways to choose 3 posters from 24.
2*2-*2*3 = 24 or as 23*3 = 24
4! 4 * 3 * 2 = 24 ways ==========
You can represent an algorithm by three different ways: 1. Pseudo Code 2. Structured flow charts 3. Actual code
4! = 4*3*2*1 = 24 ways
4*3*2*1 = 24 ways.4*3*2*1 = 24 ways.4*3*2*1 = 24 ways.4*3*2*1 = 24 ways.
24 Ways, 4 x 3 x 2 x 1 = 24
To find the number of ways to choose 3 posters from 24, you can use the combination formula, which is given by ( C(n, r) = \frac{n!}{r!(n - r)!} ). Here, ( n = 24 ) and ( r = 3 ). Plugging in the values, we get ( C(24, 3) = \frac{24!}{3!(24 - 3)!} = \frac{24 \times 23 \times 22}{3 \times 2 \times 1} = 2024 ). Thus, there are 2024 ways to choose 3 posters from 24.
2*2-*2*3 = 24 or as 23*3 = 24
4! 4 * 3 * 2 = 24 ways ==========
4*3*2*1 = 24 ways
6 x 4 = 24 3 x 8 = 24 2 x 12 = 24
24/30, 24 . 30 and then the little house thing --- .
24 12*2 6*2*2 3*2*2*2 You can write those 4 numbers 4! ways, meaning 4*3*2*1 = 24 ways. ( interesting how it came out to be the original number)
You can represent an algorithm by three different ways: 1. Pseudo Code 2. Structured flow charts 3. Actual code
4! = 4*3*2*1 = 24 ways
4*3*2*1 = 24 ways.