There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
The integers are -2, 0, 2 and 4.
Two consecutive even integers will be one more and one less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is 25, so the two consecutive integers are 24 and 26.
-2, -4, -6
The numbers are -4, -2, 0, and 2.
Let's represent the three consecutive integers as x, x+1, and x+2. To find their sum, we add these integers together: x + (x+1) + (x+2) = 88. Simplifying the equation gives us 3x + 3 = 88. Subtracting 3 from both sides and then dividing by 3, we find that x = 28. Therefore, the three consecutive integers are 28, 29, and 30, and their sum is indeed 88.
There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
112 and 113
The integers are -2, 0, 2 and 4.
The integers are -2, -1, 0 and 1.
Two consecutive even integers will be one more and one less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is 25, so the two consecutive integers are 24 and 26.
They are -6, -4 and -2.
They are: 97+99 = 196
-2, -4, -6
-2 + -1 + 0 + 1 = -2
The numbers are -4, -2, 0, and 2.
97 + 99 = 196