(f(g(t)))'=f'(g(t)) x g'(t) y=sqrt(3x-5) here f(t)=sqrt(t) and g(t)=3t-5, f'(t)=1/(2 sqrt(t)) and g'(t) = 3 So y'= f'(g(x)) x g'(x) = 1/(2 sqrt(3x-5) x 3 = 3/(2 sqrt(3x-5))
The temperature T in degrees Celsius (°C) is equal to the temperature T in degrees Fahrenheit (°F) minus 32, times 5/9: T(°C) = (T(°F) - 32) × 5/9 Convert 68 degrees Fahrenheit to degrees Celsius: T(°C) = (68°F - 32) × 5/9 = 20 °C
5 = Toes on a Foot
P | T T F F Q | T F T F Q' | F T F T P + Q' | F T F F The layout is the best I could do with this software. Hope it is OK.
T (f) = 9/5 (T (k) - 273.15) + 32
5 T on the F means 5 Toes on the Foot
(f(g(t)))'=f'(g(t)) x g'(t) y=sqrt(3x-5) here f(t)=sqrt(t) and g(t)=3t-5, f'(t)=1/(2 sqrt(t)) and g'(t) = 3 So y'= f'(g(x)) x g'(x) = 1/(2 sqrt(3x-5) x 3 = 3/(2 sqrt(3x-5))
T-U-F-F- Puppy - 2010 Toast of T-U-F-F- Share-a-Lair 1-5 was released on: USA: 23 October 2010
Do you mean f(t) = -16t^2 - 48t + 160? This is a function, which can't be "solved" as it is. - you could factor it: -16(t + 5)(t - 2) - you solve for f(t) = 0: t = 2, -5
Full Fathom 5 Thy Father Lies.
5 toes on a foot
5 toes on a foot
There's only one good tip: STUDY (and teachers never put too many of the same answer in a row: T T T F T F F F T T T)
The four temperature scales are Celsius ( C ) , Fahrenheit ( F ), Kelvin ( K ), and Rankine ( R ).T in C = ( 5/9 ) ( T in F - 32.0 )T in F = ( 9/5 ) ( T in C ) + 32.0T in K = T in C + 273.2T in R = T in F + 459.7
5 toes on a foot
5 = Toes on a Foot
The temperature T in degrees Celsius (°C) is equal to the temperature T in degrees Fahrenheit (°F) minus 32, times 5/9: T(°C) = (T(°F) - 32) × 5/9 Convert 68 degrees Fahrenheit to degrees Celsius: T(°C) = (68°F - 32) × 5/9 = 20 °C