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(f(g(t)))'=f'(g(t)) x g'(t) y=sqrt(3x-5) here f(t)=sqrt(t) and g(t)=3t-5, f'(t)=1/(2 sqrt(t)) and g'(t) = 3 So y'= f'(g(x)) x g'(x) = 1/(2 sqrt(3x-5) x 3 = 3/(2 sqrt(3x-5))
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If -t = 5, then t = -5
t is 10. given t/5=2 multiply both sides by 5, then T = 10
(7 + 8)/3 = t Therefore, t = 5.