Answer
116, 118, 120, 122, 124
Procedure
assume the numbers are such that the middle one is 2n,
the assumed numbers are: 2n-4, 2n-2, 2n, 2n+2, 2n+4 ..... (1)
Summation = 10n = 600
so, n = 60
Substitute with n = 60 in (1) we get the answer above
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