There are 74C3 = 74*73*72/(3*2*1) = 64,824 combinations and I have neither the time nor the inclination to generate a list. But you please feel free to do so.
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It is an even number because all numbers ending in 0,2,4,9 or 8 are all EVEN NUMBERS And all numbers ending in 1,3,5,7 or 9 are all ODD numbers
75*74*73*72*71*70*69*68/(8*7*6*5*4*3*2*1) = 16,871,053,725
The prime factors of 53 are 1 and 53, as 53 is a prime number itself. The prime factors of 74 are 1, 2, 37, and 74. Prime numbers are numbers greater than 1 that have no positive divisors other than 1 and themselves.
The average of a set of numbers is the sum of all the numbers, divided the amount of numbers in the sequence. For example, the average of 12, 14, 13, 15, and 20, would be the sum of the numbers, 74, divided by the amount of numbers in the sequence, 5. So the average is 74/5, which is 14.8.
There are (75 x 74)/2 = (75 x 37) = 2,775 unique pairs.