7
A factor of a number is any number which the original number can be divided by evenly. In this case, 29 divides by 7 to give 4 remainder 1. This remainder means that 29 does not divide evenly by 7. Thus 7 is not a factor of 29.
1 is the least common factor of the number 2, number 4 and number 7. 28 is the least common multiple of the number 2, number 4 and 7.
7
7 and/or 13
For 2 to be a factor, the number has to be even. If you multiply two odd numbers together, you get an odd number. 7 is odd, so if I multiply it by any odd number, I will get a number that doesn't have 2 as a factor (e.g. 7x5=35 which doesn't have 2 as a factor). Thus, the answer to the question is "no," not all multiples of 7 have 2 as a factor.
A factor = a number which can be divided into the given number with no remainder ie 1, 7, 49 7 * 7 = 49
The only number that could be both a factor and a multiple is 7 itself.
The prime factors of 147 are 3, 7 and 7. From those we can create all the other factors ... (3 x 7) and (7 x 7) which are 21 and 49. 1 is a factor of every number, and every number is a factor of itself. So all the factors of 147 are 1, 3, 7, 7, 21, 49 and 147
7
Since the number 7 is a prime number and not a factor of 26, the greatest common positive integer factor of 7 and 26 is 1.
7 because 7and 1 are the only factor since 7 is a prime number. 1 isn't a prime or composite number so it is 7.
Yes. Since 7 is a prime number, you have found all the prime numbers, with 7 being the final prime factor.
Factor each number into its prime factors. 14 = 2 * 7 49 = 7 * 7 We take all the prime factors they have in common, and multiply. In this case the only prime factor they have in common is 7, so that is the answer.
7-c
1 and 7
7