Since you are using integers, the first place to look would be if two sides are equal to 1 meter. Then the other two sides are 24/2 - 1 meter, or 11 meters. Once you know this, you can divide 24 by 4 (the 4 sides of a rectangle) to see that a square version of this rectangle is 6 meters. So, all of the possible dimensions (without reversed duplicates) go from 1 meter to 6 meters:
1x11
2x10
3x9
4x8
5x7
6x6
me
If the dimensions are restricted to whole numbers, then the only possibilities are 1 x 4 and 2 x 3.
The perimeter of a rectangle is the sum of its 4 sides added together.
The answer will depend on what those numbers represent and their units. It is possible that the question gives 18 and 5 units as the length and width of a rectangle and requires you to find the area and perimeter. Or It is possible that the question has given 18 in some units and 5 in some other units and requires you to determine which one could be the area and which the perimeter.
If we restrict ourselves to whole numbers, then 1 x 14 will have the least possible area.
me
If the dimensions are restricted to whole numbers, then the only possibilities are 1 x 4 and 2 x 3.
Ah, what a lovely question! To find the perimeter of a rectangle, we need to know both the length and width. Since the area is 432 square feet, we can find the dimensions by factoring 432 into pairs of numbers until we find a pair that could be the length and width of the rectangle. Once we have the dimensions, we can simply add up all the sides to find the perimeter.
The perimeter of a rectangle is the sum of its 4 sides added together.
The answer will depend on what those numbers represent and their units. It is possible that the question gives 18 and 5 units as the length and width of a rectangle and requires you to find the area and perimeter. Or It is possible that the question has given 18 in some units and 5 in some other units and requires you to determine which one could be the area and which the perimeter.
If we restrict ourselves to whole numbers, then 1 x 14 will have the least possible area.
Divide the perimeter by 2 then find two numbers that have a sum of 9.9 and a product of 24.3 which will work out as 5.4 and 4.5 by using the quadratic equation formula. Check: 2*(5.4+4.5) = 19.8 cm which is the perimeter Check: 5.4*4.5 = 24.3 square cm which is the area Therefore the dimensions of the rectangle are: 5.4 cm and 4.5 cm
In whole numbers, the greatest perimeter would be a rectangle 48 x 1, resulting in a perimeter of 98m.
You must first calculate the width, using the formula for the area of a rectangle (plug in the numbers you know into the formula, and solve for width). Once you know this, you can plug in the numbers in the formula for a rectangle's perimeter.
assuming whole numbers and you mean 14 square meters area it's 1x14 and 2x7 whole numbers and 14m perimeter 1x7 and 2x5 and 3x4
Let x and y be the dimensions of the rectangle. Therefore, x+y=107 and x*y=2310. The question is the find two real numbers such that they satisfy the above statement. There are x=77 and y=32 that satisfy the statement above
6 in by 8 in by 10 in.