Q: What are all the possible lengths for the sides of a triangle if the triangle's perimeter is 17 and the lengths of the sides are integers?

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Let's denote the perimeter of the first triangle as P. Since the triangles are congruent, the perimeter of the second triangle is also P. The sum of their perimeters is then 2P. According to the given statement, this sum is three times the perimeter of the first triangle. So we have the equation 2P = 3P. Simplifying, we find that P = 0, which is not a valid solution. Therefore, there is no triangle for which the sum of the perimeters of two congruent triangles is three times the perimeter of the first triangle.

The perimeter of any triangle is the sum of its 3 sides

You find the three sides of the triangle, and assure that they are all in the same unit, and then add the sides together to find the perimeter of the triangle.

It is necessary to mention that the two triangles are similar.Let the perimeter of the triangle MNP be x cm.Since the triangles XYZ and MNP are similar triangles,8/12 = x/80 (multiply both sides by 80)640/12 = x53.3333... = x53 3/9 = x53 1/3 = xThus, the perimeter of the triangle MNP is 53 1/3 cm.

You can't tell. There are an infinite number of triangles that all have a perimeter of 144.

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There is only one equilateral triangle with a perimeter of 60 units. Its side lengths are integers.

Let's denote the perimeter of the first triangle as P. Since the triangles are congruent, the perimeter of the second triangle is also P. The sum of their perimeters is then 2P. According to the given statement, this sum is three times the perimeter of the first triangle. So we have the equation 2P = 3P. Simplifying, we find that P = 0, which is not a valid solution. Therefore, there is no triangle for which the sum of the perimeters of two congruent triangles is three times the perimeter of the first triangle.

The perimeter of any triangle is the sum of its 3 sides

You find the three sides of the triangle, and assure that they are all in the same unit, and then add the sides together to find the perimeter of the triangle.

It is necessary to mention that the two triangles are similar.Let the perimeter of the triangle MNP be x cm.Since the triangles XYZ and MNP are similar triangles,8/12 = x/80 (multiply both sides by 80)640/12 = x53.3333... = x53 3/9 = x53 1/3 = xThus, the perimeter of the triangle MNP is 53 1/3 cm.

You can't tell. There are an infinite number of triangles that all have a perimeter of 144.

Triangles don't have a diameter. They have a base and a height.

If a "1 inch triangle" means a triangle each of whose sides is 1 inch, then there is no answer to the question. These are equilateral triangles and equilateral triangles can tesselate to form a larger equilateral triangle. The fact that the large triangle is equilateral means that its three sides are equal so that its perimeter ie the sum of the three sides must be divisible by 3. 20 is not divisible by 3.

They don't always- they don't always 'has' a smaller perimeter than other triangles. A triangle can be absolutely any size as long as it has three sides and angles that add to 180 degrees

Let the perimeter of the triangle MNO be x.Since the perimeters of similar polygons have the same ratio as any two corresponding sides, we have13/26 = 44/x (cross multiply)13x =1,144 (divide both sides by 13)x = 88Or since 13/26 = 1/2, the perimeter of the triangle MNO is twice the perimeter of the triangle HIJ, which is 88.

IF triangles 'A' and 'B' are similar (they both have the same angles),then the perimeter of 'B' is 8 times the perimeter of 'A'.If they're not similar, then the ratio of areas doesn't tell you the ratioof perimeters.

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