There is only one equilateral triangle with a perimeter of 60 units. Its side lengths are integers.
median = 100, mean = 1000 set of numbers = {a,b,100,c,d} a+b+100+c+d = 5000 As the set contains distinct numbers, and there is no range that is given in the problem, we can consider the set of numbers as {1,2,100,101,4796} So the largest possible integer can be 4796.
an integer plus and integer will always be an integer. We say integers are closed under addition.
If the integer subtracted is smaller than or equal to the first integer, then the answer is positive. Otherwise, if the integer subtracted is larger, then the answer is negative.
It is not an integer, nor can it ever be an integer. It can, however, be rounded to the nearest integer, in which case 0.1 will round to 0 to the nearest integer.
a negative integer
Three: 2, 5, 5 3, 4, 5 and 4, 4, 4
Distinct integer is a number with non fraction or decimal.
the largest integer of distinct power is 28
Only 3: [1,4,4], [2,3,4] and [3,3,3] Remeber that the sum of the lengths of any two sides MUST be greater than the third side. So triangles like [1,2,6] cannot exist.
Not always
It is: 0.5*4*4*sin(60 degrees) = 7 square cm rounded to nearest integer
To find the number of unique triangles with one side of length 5 cm and a perimeter less than or equal to 16 cm, we can denote the other two sides as (a) and (b). The perimeter condition gives us (5 + a + b \leq 16), or (a + b \leq 11). Additionally, the triangle inequality requires (a + b > 5). Thus, (6 \leq a + b \leq 11). The integer pairs ((a, b)) that satisfy these conditions can be systematically counted, leading to a total of 15 unique triangles.
Let the sides be s:- If: 0.5*s squared*sin(60 degrees) = 97.428 Then: s = square root of 97.428*2/sin(60 degrees) => 15.00001094 Perimeter: 3*15 = 45 cm
30 distinct powers are 13,14, and 1523
isosceles right triangles
10 of them.
It is 182 cm.