1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169 and 196. Fourteen of them.
The numbers would be odd, from one to seventeen.
Just count up all the even numbers which will all be divisible by 2
134 (squared = 17,956) and 12 (squared = 144) or 132 (squared = 17,424) and 26 (squared = 676)
37
Numbers up to 200 divisible by both 2 and 3 = numbers to 200 divisible by 2*3 = 6 which is int(200/6) = int(33.33) = 33
0,1,3,6,10,15,21,28,36,45,56,68,81,95,110,126,143,161,180,200. That's all the triangular numbers up to 200! I hope that's helped anyone with any thing.
1,4,9,16,25,36,49,64,81,100,121,144,169,196,225,256,289,324,361,400 All the square numbers up to 20!
5 squared + 12 squared = 169 (13 squared)
The numbers would be odd, from one to seventeen.
The two square numbers which add up to 13 are 9 (which is equal to 3 squared), and 4 (which is equal to 2 squared).
Just count up all the even numbers which will all be divisible by 2
134 (squared = 17,956) and 12 (squared = 144) or 132 (squared = 17,424) and 26 (squared = 676)
37
There are no two whole numbers which when squared sum to 62. There are infinitely may pairs of irrational numbers that when squared sum to 62, eg 1 and √61, 2 and √58
Numbers up to 200 divisible by both 2 and 3 = numbers to 200 divisible by 2*3 = 6 which is int(200/6) = int(33.33) = 33
53
There are exactly 200 of them.