11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97
The smallest digit palindrome that is the sum of two 3-digit palindromes is 121. This is achieved by adding the two 3-digit palindromes 101 and 20, both of which are palindromic. Therefore, 101 + 101 = 202, but if we consider a valid case with two different palindromes, we can use 111 and 110, which gives us 221, the next smallest palindrome. However, the smallest individual palindrome formed by the sum of any two 3-digit palindromes remains 121.
There are nine two-digit palindromes: 11, 22, 33, 44, 55, 66, 77, 88 and 99.
None. 1221 and 3443 are both 4-digit palindromes but no digit has remained the same between the two. First and fourth, second and third.
The smallest 4-digit palindrome is 1001. To find if it can be expressed as the sum of two 3-digit palindromes, consider the smallest 3-digit palindromes, which are 101, 111, 121, etc. The combination of 101 and 900 (another 3-digit palindrome) gives 1001, making 1001 the sum of two 3-digit palindromes. Thus, the answer is 1001.
No two digit prime number exists that is a multiple of 7. All two digit numbers that are multiples of 7 are compositenumbers.
There are nine two-digit palindromes: 11, 22, 33, 44, 55, 66, 77, 88 and 99.
None. 1221 and 3443 are both 4-digit palindromes but no digit has remained the same between the two. First and fourth, second and third.
9797 is the largest two digit prime number.
No two digit prime number exists that is a multiple of 7. All two digit numbers that are multiples of 7 are compositenumbers.
There are 21 two-digit prime numbers.
679 is the product of the largest single-digit prime number and the largest two-digit prime number.
11 is the smallest two-digit prime number.
The first two-digit prime number is 11.
The largest two-digit prime number is 97.
Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.
There are two possible digits for the first and last digit, and two possible digits for the centre digit, making 2 × 2 = 4 possible 3 digit palindromes from the set {1, 2}, namely the set {111, 121, 212, 222}.
The two-digit factors of 100 and 1000 are all composite.