Probability = Chance of Success / Total Chances (Chance of Success + Chance of Failure) There are 4 aces in a 52 card deck and 48 cards that are not aces. Probability of being dealt an ace = 4 / (4 + 48) = 4/52 = .0769 or about 7.7 percent
The answer will depend on the exact situation.If you are dealt a single card, the probability of that single card not being a queen is 12/13 - assuming you have no knowledge about the other cards.Here is another example. If you already hold three queens in your hand (and no other cards have been dealt), the probability of the next card being dealt being a queen is 1/49, so the probability of NOT getting a queen is 48/49 - higher than in the previous example.
The probability, if the cards are dealt often enough, is 1.On a single deal, the prob is 3.69379*10^-6
If the pack is well shuffled, the probability is 1/52.
Counting Aces as a face card, the answer is 0.0241 If Aces are not considered face cards, then the answer is 0.0181
Number of cards in a deck = 52 Number of cards that are spade = 13 Number of cards that are heart = 13 Probability that the card drawn is a spade and heart = 13/52 + 13/52 = 26/52 or 1/2
If only one card is dealt randomly from a deck of cards, the probability is 1/52.
The answer will depend on the exact situation.If you are dealt a single card, the probability of that single card not being a queen is 12/13 - assuming you have no knowledge about the other cards.Here is another example. If you already hold three queens in your hand (and no other cards have been dealt), the probability of the next card being dealt being a queen is 1/49, so the probability of NOT getting a queen is 48/49 - higher than in the previous example.
The probability, if the cards are dealt often enough, is 1.On a single deal, the prob is 3.69379*10^-6
The probability is 0. One card cannot be a club and a spade!
If the pack is well shuffled, the probability is 1/52.
Counting Aces as a face card, the answer is 0.0241 If Aces are not considered face cards, then the answer is 0.0181
Probability of 2 of clubs = 1/52 or 0.0192.
If you are drawing two cards from a full deck of cards (without jokers) then the probability will depend upon whether the the first card is replaced before the second is drawn, but the probability will also be different to being dealt a hand whilst playing Bridge (or Whist), which will again be different to being dealt a hand at Canasta. Without the SPECIFIC context of the two cards being got, I cannot give you a more specific answer.
There are 52 cards of which 26 (a half) are black. So he probability that the first card is black is 26/52= 1/2
Number of cards in a deck = 52 Number of cards that are spade = 13 Number of cards that are heart = 13 Probability that the card drawn is a spade and heart = 13/52 + 13/52 = 26/52 or 1/2
The odds of any card pulled from an ordinary deck of 52 cards being an Ace is 4 in 52 (4 aces in a deck of 52). This can be reduced to a 1 in 13 chance of any random card pulled from the deck being an Ace (or any other specific value, for that matter). That 13th last card dealt in a hand is no different than picking a random card out of the pack, regardless of what cards you deal before (face down or blindfolded or even face up, it doesn't matter). A more interesting question would be "what would the probability be of ANY of those 13 cards being an Ace?" Any takers?
The odds of being dealt exactly a full house are 694 to 1 against, which equates to a probability of 0.00144. The probability of all 5 card hands can be found, along with explanations of how to derive the probabilities, can be found at http://www.microcentrics.com/fivecard.aspx.