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What are the dimensions of a rectangle if the area is 100?
To find the dimensions of a rectangle with an area of 100, you can use the formula for the area, which is length × width = area. Therefore, if one side is denoted as length ( l ) and the other as width ( w ), the equation becomes ( l \times w = 100 ). There are many possible pairs of dimensions that satisfy this equation, such as 10 and 10, 25 and 4, or 50 and 2. The dimensions can vary as long as their product equals 100.
What are the dimensions of a rectangle with an area of fifty square feet and a perimeter of 201 feet?
Area of a rectangle = length(L) x width(W) Perimeter of a rectangle = 2L + 2W. 50 = LW : therefore W = 50/L 201 = 2L + 2 x (50/L) = 2L + 100/L : Multiply by L 201L = 2L2 + 100 : Therefore 2L2 - 201L + 100 = 0 This quadratic equation factorises (2L - 1)(L -100) = 0 When 2L - 1 = 0 then L = 1/2 When L - 100 = 0 then L = 100 The dimensions of the rectangle are therefore length = 100 ft, width = 1/2 foot
If farmer Dan has 100 feet of fencing write an inequality to find the dimensions of the rectangle with the largest perimeter that can be created using 100 feet of fencing?
To find the dimensions of a rectangle with the largest perimeter using 100 feet of fencing, we can express the perimeter ( P ) of a rectangle in terms of its length ( l ) and width ( w ) as ( P = 2l + 2w ). Since the total amount of fencing is 100 feet, we set up the inequality ( 2l + 2w \leq 100 ). Simplifying this gives ( l + w \leq 50 ). The dimensions that maximize the area (which is a related concept) would be when ( l = w = 25 ) feet, creating a square shape.
What are the dimensions of a rectangle with a perimeter of 401 feet and an area of 100 feet?
The rectangle cannot have an area of 100 feet, since that is a measure of distance and not area. Assume, therefore, that the area is 100 SQUARE feet. Suppose the rectagle has length L and width W then 2(L + W) = 401 and L*W = 100 So L = 100/W Then 2(100/W + W) = 401 Multiply by W: 2(100 + W2) = 401W or 2W2 - 401W + 200 = 0 or (2W - 1)(W-200) = 0 So W = 0.5 ft or W = 200 ft which imply that L = 200 ft or 0.5 ft respectively. So, the dimensions are 200 ft by 0.5 ft (or 6 inches).
Give the dimensions of the rectangle with an area of 100 square units and whole-number side lengths that has the largest perimeter?
w 20; l 30
What are the dimensions of a rectangle if the area is 100?
To find the dimensions of a rectangle with an area of 100, you can use the formula for the area, which is length × width = area. Therefore, if one side is denoted as length ( l ) and the other as width ( w ), the equation becomes ( l \times w = 100 ). There are many possible pairs of dimensions that satisfy this equation, such as 10 and 10, 25 and 4, or 50 and 2. The dimensions can vary as long as their product equals 100.
What are the dimensions of a rectangle with an area of fifty square feet and a perimeter of 201 feet?
Area of a rectangle = length(L) x width(W) Perimeter of a rectangle = 2L + 2W. 50 = LW : therefore W = 50/L 201 = 2L + 2 x (50/L) = 2L + 100/L : Multiply by L 201L = 2L2 + 100 : Therefore 2L2 - 201L + 100 = 0 This quadratic equation factorises (2L - 1)(L -100) = 0 When 2L - 1 = 0 then L = 1/2 When L - 100 = 0 then L = 100 The dimensions of the rectangle are therefore length = 100 ft, width = 1/2 foot
What are the dimensions of an AR 15 heavy barrel vs a bull barrel?
It will vary with the maker of the bull barrel.
What is the unit dimensions of length?
"L" is the dimensions of length.
If farmer Dan has 100 feet of fencing write an inequality to find the dimensions of the rectangle with the largest perimeter that can be created using 100 feet of fencing?
To find the dimensions of a rectangle with the largest perimeter using 100 feet of fencing, we can express the perimeter ( P ) of a rectangle in terms of its length ( l ) and width ( w ) as ( P = 2l + 2w ). Since the total amount of fencing is 100 feet, we set up the inequality ( 2l + 2w \leq 100 ). Simplifying this gives ( l + w \leq 50 ). The dimensions that maximize the area (which is a related concept) would be when ( l = w = 25 ) feet, creating a square shape.
What are the dimensions of an M4 rifle?
The dimensions of an M4 rifle are approximately 33 inches in length with a barrel length of about 14.5 inches.
What are the dimensions of a rectangle with a perimeter of 401 feet and an area of 100 feet?
The rectangle cannot have an area of 100 feet, since that is a measure of distance and not area. Assume, therefore, that the area is 100 SQUARE feet. Suppose the rectagle has length L and width W then 2(L + W) = 401 and L*W = 100 So L = 100/W Then 2(100/W + W) = 401 Multiply by W: 2(100 + W2) = 401W or 2W2 - 401W + 200 = 0 or (2W - 1)(W-200) = 0 So W = 0.5 ft or W = 200 ft which imply that L = 200 ft or 0.5 ft respectively. So, the dimensions are 200 ft by 0.5 ft (or 6 inches).
What are the dimensions of a full mattress?
l
Give the dimensions of the rectangle with an area of 100 square units and whole-number side lengths that has the largest perimeter?
w 20; l 30
What is difference between a selmer 100 clarinet barrel and a Selmer solo clarinet barrel?
Selmer 100
What is the equivilant to 100 m into pounds?
There is no sensible answer to this question. A metre is a measure of length, with dimensions [L]. A pound is a measure of mass (or currency), with dimensions [M or £]. Basic dimensional analysis teaches that you cannot convert between measures with different dimensions without additional information.
How many liters in 100 km?
None. A litre is a measure of volume, with dimensions [L3]. A kilometre is a measure of distance, with dimensions [L]. The two measure different things and basic dimensional analysis teaches that you cannot convert between measures with different dimensions such as these without additional information.
