a continuous time signals x(t) which is neither odd (or) even can be expressed as a sum of even and odd signals
let x(t)=xe(t)+xo(t)
=xe(t)= even part of x(t)
=xo(t)=odd part of x(t)
To determine if a signal is even or odd, you can use the definitions of even and odd functions. A signal ( x(t) ) is considered even if ( x(t) = x(-t) ) for all ( t ), meaning it is symmetric about the y-axis. Conversely, a signal is odd if ( x(t) = -x(-t) ), indicating it is symmetric about the origin. To calculate, you can analyze the signal's mathematical expression or plot it to visually assess its symmetry.
Yes it would Even + even = even Even + odd = odd Odd + odd = even
because that's the theory of maths even x even = even even x odd = odd even + even = even even + odd = odd
because... odd+odd=even even+odd=odd e.g 1+1+1=3 odd+odd+odd=odd
odd. odd=odd odd+odd=even odd+odd+odd=odd it keeps alternating in that fashion
all the signals can not be categorized as even and odd,signals like voice we can not categorize it as even or odd either we can say it is a complex signal.
Odd. Even + Even = Even Odd + Odd = Even Odd + Even = Even + Odd = Odd
even times even = even odd times even = even odd times odd = odd
odd * odd = odd answer even * even = even answer odd * even = even answer
Yes. Even + Even = Even, Odd + Odd = Even and Even + Odd or Odd + Even = Odd
No. Sum of odd + odd = even Sum of odd + even = odd Sum of even + even = even
Always. even + even = even odd + odd = even even + odd = odd odd + even = odd To summarise, if you add like numbers you get even, otherwise you get odd.
even times even = even odd times even = even odd times odd = odd
it is even
even times even = even odd times odd = odd even times odd = even
Yes it would Even + even = even Even + odd = odd Odd + odd = even
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