Divisible by both? 2 numbers... 45 and 90
It is: (45*110)/2 = 2475
All the integers that aren't divisible by 2. Those ending in 1,3,5,7 or 9. 11,13,15,17,19,21,23....39,41,43,45.
No. As 9 is smaller than 45 it cannot be divisible by 45. However, 9 is a FACTOR of 45; and 45 is divisible by 9.
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
what is the sum of the first 10 positive integers? To me, if you include 0 as the first integer, then the tenth integer is 9 and the sum is 45. If you don't include 0, the tenth integer is 10, and the sum is 55.
Divisible by both? 2 numbers... 45 and 90
It is a set of three positive integers.
All of them from 45 to 99 ... 55 integers.
Yes, you can have negative and positive integers.
It is: (45*110)/2 = 2475
45 is composite because it has other positive integers that it can be divided by other than 1 or 45. 45 can be divided by 5 and 9.
The least common factor of any set of integers is 1. The smallest number that is divisible by 9 and 5 is 45.
The least common factor of any set of positive integers is 1.
If a number is at least 5, and ends in "5" or "0", then it is divisible by 5. To further elaborate, If we are speaking of all numbers, the answer is an infinite number. If we limit it to positive integers, the answer is 50, 45, 40, 35, 30, 25, 20, 15, 10, 5, 0. Eleven total since 0 is a positive number.
All the integers that aren't divisible by 2. Those ending in 1,3,5,7 or 9. 11,13,15,17,19,21,23....39,41,43,45.
No. As 9 is smaller than 45 it cannot be divisible by 45. However, 9 is a FACTOR of 45; and 45 is divisible by 9.