Divisible by both? 2 numbers... 45 and 90
Of the 729 numbers that satisfy the requirement of positive integers, 104 are divisible by 7.
(7*100*101)/2 = 35,350 jpacs * * * * * What? How can there be 35,350 integers in the first 100 integers? There are 14 of them.
There are two.
There are 8 possibles.
Twenty of them.
128 of them.
Of the 729 numbers that satisfy the requirement of positive integers, 104 are divisible by 7.
Between 100 and 999 there are 448.
There are 128 integers between 100 and 1000 that are divisible by seven.
(7*100*101)/2 = 35,350 jpacs * * * * * What? How can there be 35,350 integers in the first 100 integers? There are 14 of them.
8 of them.
The sum of the integers from 1 to 100 inclusive is 5,050.
There are two.
450450450450
There are 8 possibles.
you can say that 2/10 of every 10 integers is divisible by 5, so multiplying 2/10 by 100, giving you 200/1000 total integers are divisible by 5. half of all integers are odd, so divide 200/1000 by 2 is 100/1000, so you can correctly state that 100 odd integers under 1000 are divisible by 5.
Seven of them.