The numbers are -2, -1, 0, 1 and 2.
Let the five consecutive integers be ( x-2, x-1, x, x+1, x+2 ). The sum of these integers can be expressed as ( (x-2) + (x-1) + x + (x+1) + (x+2) = 5x ). To find the integers that sum to 0, we set ( 5x = 0 ) which gives ( x = 0 ). Thus, the five consecutive integers are -2, -1, 0, 1, and 2.
There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
The integers are -2, 0, 2 and 4.
-2, -1, 0, 1
The numbers are -4, -2, 0, and 2.
Let the five consecutive integers be ( x-2, x-1, x, x+1, x+2 ). The sum of these integers can be expressed as ( (x-2) + (x-1) + x + (x+1) + (x+2) = 5x ). To find the integers that sum to 0, we set ( 5x = 0 ) which gives ( x = 0 ). Thus, the five consecutive integers are -2, -1, 0, 1, and 2.
-1, 0, 1
Well, well, well, look who's trying to do some math! If the sum of ten consecutive integers is five, then the middle number is 0. So, the largest integer would be 4. Keep crunching those numbers, honey!
There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
The integers are -2, 0, 2 and 4.
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
The integers are -2, -1, 0 and 1.
-2, -1, 0, 1
1+8+0 = 9 or 180+80+0 = 260
-2, -1, 0, 1
-2 + -1 + 0 + 1 = -2
The numbers are -4, -2, 0, and 2.